NUMMIT #67 — TARGET 709

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Nummit #67 — target 709 (Hard)

This was the daily Nummit puzzle for May 7, 2026. The six numbers were 50, 75, 5, 4, 1, 1 and the target was 709. It is rated Hard, and the shortest solution takes 4 steps. Playing it here is practice mode, so it won't change your daily streak.

About this puzzle

  • The numbers: 2 large (75, 50) and 4 small (5, 4, 1, 1).
  • The target: 709 is a prime number, so it can't be reached by multiplying two smaller whole numbers. The nearest starting number is 75, 634 away, so you have to build the target rather than start next to it.
  • Difficulty: It is rated Hard because the shortest route needs 4 operations and the target sits far from every starting number, so there is no quick shortcut.
  • Tip: With 75 and 50 on the board, try combining the large numbers first and fine-tune with the small ones.

Nummit #67 answer

Reveal solution

One shortest solution (4 steps)

  1. 1. 50 ÷ 5 = 10
  2. 2. 75 - 4 = 71
  3. 3. 10 × 71 = 710
  4. 4. 710 - 1 = 709

In words

  1. Divide 50 by 5 to get 10.
  2. Subtract 4 from 75 to leave 71.
  3. Multiply 10 by 71 to get 710.
  4. Subtract 1 from 710 to leave 709.

Other routes to 709 may exist; this is just one with the fewest steps.

Puzzles from the same week

Helpful answers

Frequently asked questions

How hard was Nummit #67?
Nummit #67 (May 7, 2026) is rated Hard. The target was 709 and a shortest solution takes 4 steps. It is rated Hard because the shortest route needs 4 operations and the target sits far from every starting number, so there is no quick shortcut.
Do I have to use all six numbers in Nummit #67?
No. Nummit never requires every number. A shortest solution to this puzzle uses 5 of the six, and each number can be used once.
What were the numbers in Nummit #67?
50, 75, 5, 4, 1, 1, with a target of 709. The large numbers were 75 and 50.
Can I still play Nummit #67?
Yes. The board above is this exact puzzle in practice mode, so it doesn't affect your daily streak. You can check your answer afterwards by opening the solution on this page.