NUMMIT #35 — TARGET 957

Loading…

Nummit #35 — target 957 (Hard)

This was the daily Nummit puzzle for April 5, 2026. The six numbers were 50, 25, 1, 6, 2, 1 and the target was 957. It is rated Hard, and the shortest solution takes 5 steps. Playing it here is practice mode, so it won't change your daily streak.

About this puzzle

  • The numbers: 2 large (50, 25) and 4 small (6, 2, 1, 1).
  • The target: 957 = 3 × 11 × 29. The nearest starting number is 50, 907 away, so you have to build the target rather than start next to it.
  • Difficulty: It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
  • Tip: With 50 and 25 on the board, try combining the large numbers first and fine-tune with the small ones.

Nummit #35 answer

Reveal solution

One shortest solution (5 steps)

  1. 1. 50 - 1 = 49
  2. 2. 6 × 49 = 294
  3. 3. 25 + 294 = 319
  4. 4. 2 + 1 = 3
  5. 5. 319 × 3 = 957

In words

  1. Subtract 1 from 50 to leave 49.
  2. Multiply 6 by 49 to get 294.
  3. Add 25 and 294 to make 319.
  4. Add 2 and 1 to make 3.
  5. Multiply 319 by 3 to get 957.

Other routes to 957 may exist; this is just one with the fewest steps.

Puzzles from the same week

Helpful answers

Frequently asked questions

How hard was Nummit #35?
Nummit #35 (April 5, 2026) is rated Hard. The target was 957 and a shortest solution takes 5 steps. It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
Do I have to use all six numbers in Nummit #35?
No. Nummit never requires every number. A shortest solution to this puzzle uses 6 of the six, and each number can be used once.
What were the numbers in Nummit #35?
50, 25, 1, 6, 2, 1, with a target of 957. The large numbers were 50 and 25.
Can I still play Nummit #35?
Yes. The board above is this exact puzzle in practice mode, so it doesn't affect your daily streak. You can check your answer afterwards by opening the solution on this page.