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NUMMIT #16 — TARGET 640

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Nummit #16 — target 640 (Hard)

This was the daily Nummit puzzle for March 17, 2026. The six numbers were 50, 25, 1, 3, 1, 4 and the target was 640. It is rated Hard, and the shortest solution takes 5 steps. Playing it here is practice mode, so it won't change your daily streak.

About this puzzle

  • The numbers: 2 large (50, 25) and 4 small (4, 3, 1, 1).
  • The target: 640 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 5. The nearest starting number is 50, 590 away, so you have to build the target rather than start next to it.
  • Difficulty: It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
  • Tip: With 50 and 25 on the board, try combining the large numbers first and fine-tune with the small ones.

Nummit #16 answer

Reveal solution

One shortest solution (5 steps)

  1. 1. 50 + 1 = 51
  2. 2. 3 × 51 = 153
  3. 3. 1 + 4 = 5
  4. 4. 153 - 25 = 128
  5. 5. 5 × 128 = 640

In words

  1. Add 50 and 1 to make 51.
  2. Multiply 3 by 51 to get 153.
  3. Add 1 and 4 to make 5.
  4. Subtract 25 from 153 to leave 128.
  5. Multiply 5 by 128 to get 640.

Other routes to 640 may exist; this is just one with the fewest steps.

Puzzles from the same week

Helpful answers

Frequently asked questions

How hard was Nummit #16?
Nummit #16 (March 17, 2026) is rated Hard. The target was 640 and a shortest solution takes 5 steps. It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
Do I have to use all six numbers in Nummit #16?
No. Nummit never requires every number. A shortest solution to this puzzle uses 6 of the six, and each number can be used once.
What were the numbers in Nummit #16?
50, 25, 1, 3, 1, 4, with a target of 640. The large numbers were 50 and 25.
Can I still play Nummit #16?
Yes. The board above is this exact puzzle in practice mode, so it doesn't affect your daily streak. You can check your answer afterwards by opening the solution on this page.