NUMMIT #142 — TARGET 871

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Nummit #142 — target 871 (Hard)

This was the daily Nummit puzzle for July 21, 2026. The six numbers were 25, 75, 10, 9, 4, 1 and the target was 871. It is rated Hard, and the shortest solution takes 5 steps. Playing it here is practice mode, so it won't change your daily streak.

About this puzzle

  • The numbers: 2 large (75, 25) and 4 small (10, 9, 4, 1).
  • The target: 871 = 13 × 67. The nearest starting number is 75, 796 away, so you have to build the target rather than start next to it.
  • Difficulty: It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
  • Tip: With 75 and 25 on the board, try combining the large numbers first and fine-tune with the small ones.

Nummit #142 answer

Reveal solution

One shortest solution (5 steps)

  1. 1. 25 + 75 = 100
  2. 2. 9 + 4 = 13
  3. 3. 100 - 13 = 87
  4. 4. 10 × 87 = 870
  5. 5. 1 + 870 = 871

In words

  1. Add 25 and 75 to make 100.
  2. Add 9 and 4 to make 13.
  3. Subtract 13 from 100 to leave 87.
  4. Multiply 10 by 87 to get 870.
  5. Add 1 and 870 to make 871.

Other routes to 871 may exist; this is just one with the fewest steps.

Puzzles from the same week

Helpful answers

Frequently asked questions

How hard was Nummit #142?
Nummit #142 (July 21, 2026) is rated Hard. The target was 871 and a shortest solution takes 5 steps. It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
Do I have to use all six numbers in Nummit #142?
No. Nummit never requires every number. A shortest solution to this puzzle uses 6 of the six, and each number can be used once.
What were the numbers in Nummit #142?
25, 75, 10, 9, 4, 1, with a target of 871. The large numbers were 75 and 25.
Can I still play Nummit #142?
Yes. The board above is this exact puzzle in practice mode, so it doesn't affect your daily streak. You can check your answer afterwards by opening the solution on this page.