clevr.tools

NUMMIT #115 — TARGET 494

Loading…

Nummit #115 — target 494 (Hard)

This was the daily Nummit puzzle for June 24, 2026. The six numbers were 25, 75, 3, 8, 3, 9 and the target was 494. It is rated Hard, and the shortest solution takes 5 steps. Playing it here is practice mode, so it won't change your daily streak.

About this puzzle

  • The numbers: 2 large (75, 25) and 4 small (9, 8, 3, 3).
  • The target: 494 = 2 × 13 × 19. The nearest starting number is 75, 419 away, so you have to build the target rather than start next to it.
  • Difficulty: It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
  • Tip: With 75 and 25 on the board, try combining the large numbers first and fine-tune with the small ones.

Nummit #115 answer

Reveal solution

One shortest solution (5 steps)

  1. 1. 25 + 75 = 100
  2. 2. 8 - 3 = 5
  3. 3. 9 - 3 = 6
  4. 4. 100 × 5 = 500
  5. 5. 500 - 6 = 494

In words

  1. Add 25 and 75 to make 100.
  2. Subtract 3 from 8 to leave 5.
  3. Subtract 3 from 9 to leave 6.
  4. Multiply 100 by 5 to get 500.
  5. Subtract 6 from 500 to leave 494.

Other routes to 494 may exist; this is just one with the fewest steps.

Puzzles from the same week

Helpful answers

Frequently asked questions

How hard was Nummit #115?
Nummit #115 (June 24, 2026) is rated Hard. The target was 494 and a shortest solution takes 5 steps. It is rated Hard because the shortest route needs 5 operations and the target sits far from every starting number, so there is no quick shortcut.
Do I have to use all six numbers in Nummit #115?
No. Nummit never requires every number. A shortest solution to this puzzle uses 6 of the six, and each number can be used once.
What were the numbers in Nummit #115?
25, 75, 3, 8, 3, 9, with a target of 494. The large numbers were 75 and 25.
Can I still play Nummit #115?
Yes. The board above is this exact puzzle in practice mode, so it doesn't affect your daily streak. You can check your answer afterwards by opening the solution on this page.